SOLUTION TO PUZZLE 1(KING AND WINE BOTTLES)

SOLUTION:
for question see:king and wine puzzle
Some of you might already had seen the solution of this puzzle in binary form like following:

Number the bottles 1 to 1000 and write the number in binary format like bottle 1 = 0000000001 bottle  2=0000000010 ans so on.
now take 10 prisoners and number them 1 to 10, now let prisoner 1 take a sip from every bottle that has a 1 in its least significant bit. Let prisoner 10 take a sip from every bottle with a 1 in its most significant bit. etc.

prisoner = 10 9 8 7 6 5 4 3 2 1
bottle 845= 1 1 0 1 0 0 1 1 0 1



For instance, bottle no. 845 would be sipped by 10,9,7,4,3 and 1. That way if bottle no. 845 was the poisoned one, only those prisoners would die.So after 4 weeks you have to check who had died and you can find that bottle.But this solution is somewhat artificial as some of my friends say.See the following

first let us take 1 prisoner,he can drink one bottle if its poisoned he will die.so this way u will need 1000 prisoners
Take 2 prisoners and name them as a1,a2
their group 
is like
a1
a2
a1,a2
none  total:4=2^2
and make this four groups drink 4 bottles(named) if a2 alone dies u can identify that bottle

Take 3 prisoners a1,a2,a3.group them as
a1
a2
a3
a1,a2
a2,a3
a1,a3
a1,a2,a3
none total:8=2^3 if a1,a2 alone dead that wine bottle is poisoned

so to test  1000 bottle
2^n>1000

which gives the answer n=10

any comments and suggestions are welcome. 

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